(2^1/2)^4y=1/8

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Solution for (2^1/2)^4y=1/8 equation: 



(2^1/2)^4y=1/8

We move all terms to the left:

(2^1/2)^4y-(1/8)=0



Domain of the equation: 2)^4y!=0

y!=0/1

y!=0

y∈R



We add all the numbers together, and all the variables

(2^1/2)^4y-(+1/8)=0

We get rid of parentheses

(2^1/2)^4y-1/8=0

We calculate fractions


()/2^4y*8)+(-2y)/2^4y*8)=0

We calculate fractions

We do not support eypression: y^10

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